Mail Archives: djgpp/2011/09/10/10:47:55
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| From: | Sterten AT aol DOT com
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| Message-ID: | <8c30b.37d5743f.3b9cd022@aol.com>
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| Date: | Sat, 10 Sep 2011 10:37:22 -0400 (EDT)
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| Subject: | Re: A printf problem?
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| To: | djgpp AT delorie DOT com
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=20
you may have a typo
52258 for the first, not 55258
=20
=20
=20
In einer eMail vom 10.09.2011 15:45:30 Westeurop=E4ische Normalzeit schreib=
t =20
mok-kong DOT shen AT t-online DOT de:
Hi,
Maybe I have made a very grave mistake, but I just can't yet understand
why the code attached below produced the following output:
first: cc22 55258
second: d7da 55258
third: ffff 65535
Why are the first two numbers, which are different hexadecimals,
printed out as the same decimal number?
Thanks for your kind help in advance.
M. K. Shen
------------------------------------------------------
#include <stdio.h>
int main()
{ unsigned long int g;
g=3D0xcc22; printf("first: %8x %10lu\n",g,g);
g=3D0xd7da; printf("second: %8x %10lu\n",g,g);
g=3D0xffff; printf("third: %8x %10lu\n",g,g);
return(0);
}
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<HTML><HEAD>
<META http-equiv=3DContent-Type content=3D"text/html; charset=3DISO-8859-1"=
>
<META content=3D"MSHTML 6.00.5730.11" name=3DGENERATOR></HEAD>
<BODY id=3Drole_body style=3D"FONT-SIZE: 10pt; COLOR: #000000; FONT-FAMILY:=
Arial"=20
bottomMargin=3D7 leftMargin=3D7 topMargin=3D7 rightMargin=3D7><FONT id=3Dro=
le_document=20
face=3DArial color=3D#000000 size=3D2>
<DIV>
<DIV>you may have a typo</DIV>
<DIV>52258 for the first, not 55258</DIV>
<DIV> </DIV>
<DIV> </DIV>
<DIV> </DIV>
<DIV>In einer eMail vom 10.09.2011 15:45:30 Westeurop=E4ische Normalzeit sc=
hreibt=20
mok-kong DOT shen AT t-online DOT de:</DIV>
<BLOCKQUOTE=20
style=3D"PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: blue 2px solid">=
<FONT=20
style=3D"BACKGROUND-COLOR: transparent" face=3DArial color=3D#000000=20
size=3D2>Hi,<BR><BR>Maybe I have made a very grave mistake, but I just ca=
n't yet=20
understand<BR>why the code attached below produced the following=20
output:<BR><BR>first: cc22 =
=20
55258<BR>second: d7da =20
55258<BR>third: ffff =20
65535<BR><BR>Why are the first two numbers, which are different=20
hexadecimals,<BR>printed out as the same decimal number?<BR><BR>Thanks fo=
r=20
your kind help in advance.<BR><BR>M. K.=20
Shen<BR><BR>------------------------------------------------------<BR>#in=
clude=20
<stdio.h><BR><BR>int main()<BR>{ unsigned long int=20
g;<BR><BR> g=3D0xcc22; printf("first: %8x =20
%10lu\n",g,g);<BR><BR> g=3D0xd7da; printf("second: %8x =
=20
%10lu\n",g,g);<BR><BR> g=3D0xffff; printf("third: %8x&n=
bsp;=20
%10lu\n",g,g);<BR><BR> return(0);<BR>}<BR></FONT></BLOCKQUOTE=
></DIV>
<DIV></DIV>
<DIV> </DIV></FONT></BODY></HTML>
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