From: Anatoly AT delorie DOT com
Newsgroups: comp.os.msdos.djgpp
Subject: Re: why does this work like this (char allocation question)??
Date: 13 Aug 1997 21:56:54 -0700
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In article , "Smith says...
>
>when i run this:
>
...
>
>to impatience...)  it echos the input string, and prints *4* for the
>size.  when the string gets longer, it segs out.
>
It prints 4 because it's size of the pointer (yes, if you declare buffer[4],
buffer is still a pointer).
>why doesn't it seg out as soon as the string exceeds four characters??
>
>the same thing happens if you declare the string as a pointer (*buffer).
>
>does a declared variable name automagically get 64 bytes of exercise
>space??
>
>phil
>

But other your questions pussled me too.